document.write( "Question 599684: I've got another one I'd like help with please.
\n" ); document.write( "A metallurgist has one alloy containing 21% aluminum and another containing 67% aluminum. How many pounds of each alloy must he use to make 57 pounds of a third alloy containing 23% aluminum? the answer should be rounded to the nearest hundredth. if this could be explained how to set it up with the answer, so hopefully I can help my step daughter with her remaining questions. Thank you \n" ); document.write( "
Algebra.Com's Answer #379048 by ankor@dixie-net.com(22740)\"\" \"About 
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A metallurgist has one alloy containing 21% aluminum and another containing 67% aluminum.
\n" ); document.write( " How many pounds of each alloy must he use to make 57 pounds of a third alloy containing 23% aluminum?
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\n" ); document.write( "Let x = amt of 67% Alum
\n" ); document.write( "the result is to be 57 lb, therefore
\n" ); document.write( "(57-x) = amt of 21% Alum
\n" ); document.write( ":
\n" ); document.write( "A typical mixture equation using decimal equiv
\n" ); document.write( ".67x + .21(57-x) = .23(57)
\n" ); document.write( ".67x + 11.97 - .21x = 13.11
\n" ); document.write( ".67x - .21x = 13.11 - 11.97
\n" ); document.write( ".46x = 1.14
\n" ); document.write( "x = 1.14/.46 =
\n" ); document.write( "x = 2.48 lb of the 67% alloy required
\n" ); document.write( "then
\n" ); document.write( "57 - 2.48 = 54.52 lb of the 21% alloy
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