document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=599666>Question 599666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One more then I'm done, my son has another problem on his homework that calls for the Gaussian elimination method with back substitution to solve the given system of these linear equations. would some be will to help explain this process a little clearer. the equations were -9x-45y= -27<BR>\n" );
document.write( "                                     x-  y= -1\r<BR>\n" );
document.write( "\n" );
document.write( "thanks in advance shannii </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #379037 by </B><A HREF=/tutors/aboutme.mpl?userid=lynnlo><B>lynnlo(4176)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lynnlo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=379037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SUBSTITUTION METHOD:<BR>\n" );
document.write( " -9x-45y=-27<BR>\n" );
document.write( "   x-y=-1<BR>\n" );
document.write( " ANSWER:<BR>\n" );
document.write( "     y=2/3<BR>\n" );
document.write( "x=-1/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );