document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=599478>Question 599478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves a country town travelling at 60km/h. Two hours later a second car leaves the town and catches up to the first car in five hours. Find the speed of the second car. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378974 by </B><A HREF=/tutors/aboutme.mpl?userid=Nihal@SriLanka><B>Nihal@SriLanka(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nihal@SriLanka><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem could also be solved without resorting to algebraic notation.\r<BR>\n" );
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document.write( "By the time the second car catches up with the first car it has traveled a total of seven hours at a speed of 60 km per hour which implies it had traveled a total distance of 60 into 7, i.e. 420 kilometers. Since the second car has to catch up this distance in 5 hours it has to travel at a speed of 420 by 5, i.e. 84 km per hour.  </SPAN>\n" );
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