document.write( "Question 599466: What is the vertex, focus, axis of symmetry and focal diameter of the equation 9y^2+36x+18y-63=0 \n" ); document.write( "
Algebra.Com's Answer #378962 by lwsshak3(11628)\"\" \"About 
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What is the vertex, focus, axis of symmetry and focal diameter of the equation
\n" ); document.write( "9y^2+36x+18y-63=0
\n" ); document.write( "complete the square
\n" ); document.write( "9(y^2+2y+1)+36x-63-9=0
\n" ); document.write( "9(y+1)^2=-36x+72=-36(x-2)
\n" ); document.write( "(y+1)^2=-4(x-2)
\n" ); document.write( "This is an equation of a parabola which opens leftwards.
\n" ); document.write( "Its standard form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of vertex
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex: (2,-1)
\n" ); document.write( "axis of symmetry: y=-1
\n" ); document.write( "4p=4
\n" ); document.write( "p=1
\n" ); document.write( "focus: (1,-1) (p distance from vertex on the axis of symmetry)
\n" ); document.write( "focal diameter=4p=4 \n" ); document.write( "
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