document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=599461>Question 599461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem: the difference between the measures of two complementary angles is 14. Find both angles.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378957 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Please help me solve this problem: the difference between the measures of two complementary angles is 14. Find both angles. <BR>\n" );
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document.write( "Two angles are complementary if the sum of the two angles equals 90 degrees.<BR>\n" );
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document.write( "Let x = measure of one angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "90-x = measure of second angle<BR>\n" );
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document.write( "x - (90-x) = 14<BR>\n" );
document.write( "x - 90+x = 14<BR>\n" );
document.write( "2x - 90 = 14<BR>\n" );
document.write( "2x = 104<BR>\n" );
document.write( "x = 52 degrees<BR>\n" );
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document.write( "second angle:<BR>\n" );
document.write( "90-x = 90-54 = 36 degrees<BR>\n" );
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document.write( "answer: 52 and 36 degrees </SPAN>\n" );
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