document.write( "Question 599404: A rectangle is six times as long as it is wide. Determine the ratio of its area to its perimeter (A/P), in simplest form, if the width is w. \n" ); document.write( "
Algebra.Com's Answer #378934 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! P = 2L+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 6W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 2(6W)+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 12W+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 14W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = LW\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = (6W)W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = 6W^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A/P\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(6W^2)/(14W)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(3W)/7\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the ratio A/P is (3W)/7\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can write the ratio as (3W)/7:1 or as 3W:7 \n" ); document.write( " |