document.write( "Question 599369: What would the focus and directrix of the equation y=3x^2 -5x^2 +3?
\n" ); document.write( "I have simplified it to y= -2x^2 +3 but i don't know what to do from there.
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Algebra.Com's Answer #378923 by stanbon(75887)\"\" \"About 
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What would the focus and directrix of the equation y=3x^2 -5x^2 +3?
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\n" ); document.write( "Form: (x-h)^2 = 4p(y-k)
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\n" ); document.write( "Your Problem:
\n" ); document.write( "y = -2x^2+3
\n" ); document.write( "y-3 = -2(x-0)^2
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\n" ); document.write( "4p = -2
\n" ); document.write( "p = -1/2
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\n" ); document.write( "Vertex: (0,3)
\n" ); document.write( "The parabola opens down so focus is at: (0,3-(1/2) = (0,5/2)
\n" ); document.write( "Directrix is y = 3-(-1/2) = 7/2
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\n" ); document.write( "\"graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C-2x%5E2%2B3%29\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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