document.write( "Question 599369: What would the focus and directrix of the equation y=3x^2 -5x^2 +3?
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document.write( "I have simplified it to y= -2x^2 +3 but i don't know what to do from there. \n" );
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Algebra.Com's Answer #378923 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! What would the focus and directrix of the equation y=3x^2 -5x^2 +3? \n" ); document.write( "---- \n" ); document.write( "Form: (x-h)^2 = 4p(y-k) \n" ); document.write( "---------- \n" ); document.write( "Your Problem: \n" ); document.write( "y = -2x^2+3 \n" ); document.write( "y-3 = -2(x-0)^2 \n" ); document.write( "----- \n" ); document.write( "4p = -2 \n" ); document.write( "p = -1/2 \n" ); document.write( "---------- \n" ); document.write( "Vertex: (0,3) \n" ); document.write( "The parabola opens down so focus is at: (0,3-(1/2) = (0,5/2) \n" ); document.write( "Directrix is y = 3-(-1/2) = 7/2 \n" ); document.write( "==================== \n" ); document.write( " \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================== \n" ); document.write( " |