document.write( "Question 599358: A container has 12 light bulbs, 4 of which are defective. Select 4 light bulbs. How many ways can we get 3 good and 1 bad light bulbs? \n" ); document.write( "
Algebra.Com's Answer #378919 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
(8 C 3)*(4 C 1) = [ (8!)/(3!(8-3)!) ] * [ (4!)/(1!(4-1)!) ] = 56*4 = 224\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So there are 224 ways.
\n" ); document.write( "
\n" );