document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=599299>Question 599299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangular garden is 5 m greater than the width. the area is 104m^2. find the dimensions of the garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378892 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = LW\r<BR>\n" );
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document.write( "104 = (W+5)W\r<BR>\n" );
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document.write( "104 = W(W+5)\r<BR>\n" );
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document.write( "W^2 + 5W - 104 = 0\r<BR>\n" );
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document.write( "Now use the quadratic formula to solve\r<BR>\n" );
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document.write( "W = (-b+-sqrt(b^2-4ac))/(2a)\r<BR>\n" );
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document.write( "W = (-(5)+-sqrt((5)^2-4(1)(-104)))/(2(1))\r<BR>\n" );
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document.write( "W = (-5+-sqrt(25-(-416)))/(2)\r<BR>\n" );
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document.write( "W = (-5+-sqrt(441))/2\r<BR>\n" );
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document.write( "W = (-5+sqrt(441))/2 or W = (-5-sqrt(441))/2\r<BR>\n" );
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document.write( "W = (-5+21)/2 or W = (-5-21)/2\r<BR>\n" );
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document.write( "W = 16/2 or W = -26/2\r<BR>\n" );
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document.write( "W = 8 or W = -13\r<BR>\n" );
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document.write( "Throw out the negative solution to be left with the only solution of W = 8\r<BR>\n" );
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document.write( "So the width is 8 m and length is 13 m (since  L = W+5 = 8+5 = 13) </SPAN>\n" );
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