document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=599271>Question 599271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carbon 14 decays continously at the rate of 0.01245% per year. If 13% of the original carbon-14 remains in a specimen, estimate its age in years. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378881 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Carbon 14 decays continously at the rate of 0.01245% per year. If 13% of the original carbon-14 remains in a specimen, estimate its age in years.---------------------------------------<BR>\n" );
document.write( "A(t) = Ao^t<BR>\n" );
document.write( "------<BR>\n" );
document.write( "0.13Ao = Ao^t<BR>\n" );
document.write( "----<BR>\n" );
document.write( "0.13 = 0.999875^t<BR>\n" );
document.write( "--- <BR>\n" );
document.write( "Take the ln of both sides:<BR>\n" );
document.write( "t = ln(0.13)/ln(0.99875)<BR>\n" );
document.write( "t = 1631 years<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );