document.write( "Question 599205: x^2+y^2+8x-6y=0
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document.write( "find the center and radius \n" );
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Algebra.Com's Answer #378876 by math-vortex(648)![]() ![]() You can put this solution on YOUR website! Hi, there-- \n" ); document.write( ". \n" ); document.write( "The equation for a circle has the form \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The ordered pair (h,k) is the center of the circle and r is the radius. We need to transform the given equation to this form to find the center and radius. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We will use the \"completing the square\" method. The polynomial x^2+8x+16 is a perfect square [(8/2)^2=16], so we need to add 16 to both sides of the equation and re-arrange the terms. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The polynomial y^2-6y+9 is a perfect square, so we need to add 9 to both sides of the equation. \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now write the polynomial expressions in factored form. \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then write the constant term as the square of a number. \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The equation is now in standard form, so the center=(h,k) is (-4,3), and the radius is 5. \n" ); document.write( ". \n" ); document.write( "That's it. Feel free to email via my gmail account if you have questions about the solution. \n" ); document.write( ". \n" ); document.write( "Ms.Figgy \n" ); document.write( "math.in.the.vortex@gmail.com \n" ); document.write( " |