document.write( "Question 55854This question is from textbook heath algebra I an intergrated approach
\n" ); document.write( ": between 1970 and 1990, missouri's population increased at the rate of0.47%per year. thepopulation,p, in year t is given by
\n" ); document.write( " p = 4,903,000 * 1.0047t where t=0 corresponds to 1980. find the populationin 1970,1980, and 1990. i understand that 1980 = 4,903,000 but can't
\n" ); document.write( "figure out the formula to get the correct answers.
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Algebra.Com's Answer #37884 by Cintchr(481)\"\" \"About 
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Double check your book for the given terms. Since 1970 is the first year, it should be the 0 value.
\n" ); document.write( "\"+p+=++4903000+%2A+1.0047t+\"
\n" ); document.write( "t=0 is 1970
\n" ); document.write( "t=10 is 1980
\n" ); document.write( "t=20 is 1990
\n" ); document.write( "Plug 10 in for t
\n" ); document.write( "\"+p+=++4903000+%2A+1.0047t+\"
\n" ); document.write( "\"+p+=++4903000+%2A+1.0047%2810%29+\"
\n" ); document.write( "Multiply
\n" ); document.write( "\"+p+=++4903000+%2A+10.047+\"
\n" ); document.write( "Multiply again
\n" ); document.write( "\"+p+=+4926044.1+\"
\n" ); document.write( "Assuming that t=10 for 1980 ... this is the population.
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