document.write( "Question 599123: Does anyone know how to do this type of problem? I am stuck, and would appreciate any help. Thanks!\r
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Algebra.Com's Answer #378838 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"s%5E6-729\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28s%5E2%29%5E3-%289%29%5E3\" Rewrite \"s%5E6\" as \"%28s%5E2%29%5E3\". Rewrite \"729\" as \"%289%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28s%5E2-9%29%28%28s%5E2%29%5E2%2B%28s%5E2%29%289%29%2B%289%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28s%5E2-9%29%28s%5E4%2B9s%5E2%2B81%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%28s-3%29%28s%2B3%29%28s%5E4%2B9s%5E2%2B81%29\" Now factor \"s%5E2-9\" to get \"%28s-3%29%28s%2B3%29\" (using the difference of squares rule)\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"s%5E6-729\" factors to \"%28s-3%29%28s%2B3%29%28s%5E4%2B9s%5E2%2B81%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"s%5E6-729=%28s-3%29%28s%2B3%29%28s%5E4%2B9s%5E2%2B81%29\" for all values of 's'\r
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