document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=599110>Question 599110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the shaded are of a quadrilateral if the quadrilateral is a square and all arcs are arcs of a circle of radius 6 cm and there are four arcs one for each corner? Thanks for helping :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378837 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This square is inscribed in the circle of radius 6. So the diagonal of the square is 2*6 = 12 cm\r<BR>\n" );
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document.write( "Let x = length of the side of the square\r<BR>\n" );
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document.write( "So by the pythagorean theorem\r<BR>\n" );
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document.write( "a^2 + b^2 = c^2\r<BR>\n" );
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document.write( "x^2 + x^2 = 12^2\r<BR>\n" );
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document.write( "2x^2 = 144\r<BR>\n" );
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document.write( "x^2 = 144/2\r<BR>\n" );
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document.write( "x^2 = 72\r<BR>\n" );
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document.write( "x = sqrt(72)\r<BR>\n" );
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document.write( "x = 6*sqrt(2)\r<BR>\n" );
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document.write( "So the length of the side of the square is 6*sqrt(2) cm\r<BR>\n" );
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document.write( "Now use it in the area for a square formula\r<BR>\n" );
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document.write( "A = s^2\r<BR>\n" );
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document.write( "A = (6*sqrt(2))^2\r<BR>\n" );
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document.write( "A = (6*6)*(sqrt(2)*sqrt(2))\r<BR>\n" );
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document.write( "A = 36*sqrt(4)\r<BR>\n" );
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document.write( "A = 36*2\r<BR>\n" );
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document.write( "A = 72\r<BR>\n" );
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document.write( "So the area of the square is 72 square cm. </SPAN>\n" );
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