document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=599096>Question 599096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Last year a store sold 600 hats for $15 a peice. Increasing the price this year, For every $1 increase they will sell 30 less hats.<BR>\n" );
document.write( "what should the selling price be for max profit.<BR>\n" );
document.write( "Max revenue,\r<BR>\n" );
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document.write( "I used the equation (600 - 30x) (15 +1x) but I don't know if that's right.<BR>\n" );
document.write( "The final answer is $17.50 per hat and a total profit of $9187.5 but I don't know how to get there </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378824 by </B><A HREF=/tutors/aboutme.mpl?userid=flame8855><B>flame8855(424)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=flame8855><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=flame8855><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equatio is right <BR>\n" );
document.write( "now for determining the maximum value for x set the derivative of the equation equal to zero<BR>\n" );
document.write( "f(x)=(600 - 30x) (15 +1x) = 9000+600x-450x-30x^2<BR>\n" );
document.write( "f'(x)= 600-450-60x=0<BR>\n" );
document.write( "150=60x , x=5/2=2.5<BR>\n" );
document.write( "maximun value for hat : 15+x=15+2.5=17.5<BR>\n" );
document.write( "f(x) is the total profit = (600-30(2.5))(17.5)= 9187.5<BR>\n" );
document.write( " </SPAN>\n" );
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