document.write( "Question 598945: Please help me find the standard form (function) of this quadratic equation.\r
\n" ); document.write( "\n" ); document.write( "3q+100=-q2/2000-4q+1000 \n" ); document.write( "

Algebra.Com's Answer #378820 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"3q+%2B+100+=+-q%5E2%2F2000+-4q+%2B+1000\"$
\n" ); document.write( "0 = $\"-q%5E2%2F2000+-+4q+-+3q+%2B+1000+-+100\"$
\n" ); document.write( "0 = $\"-q%5E2%2F2000+-+7q+%2B+900\"$
\n" ); document.write( "Multiply both sides by 2000
\n" ); document.write( "0 = $\"-q%5E2+-+14000q+%2B+1800000\"$
\n" ); document.write( "f(q) = 0, therefore
\n" ); document.write( "f(q) = $\"-q%5E2+-+14000q+%2B+1800000\"$ \n" ); document.write( "

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