document.write( "Question 599021: log(-x)=-log(x) \n" ); document.write( "
Algebra.Com's Answer #378771 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! log(-x)=-log(x) \n" ); document.write( "-------------- \n" ); document.write( "log(-x)+log(x) = 0 \n" ); document.write( "-- \n" ); document.write( "log[(-x)(x)] = 0 \n" ); document.write( "-- \n" ); document.write( "-x^2 = 10^0 \n" ); document.write( "--- \n" ); document.write( "-x^2 = 1 \n" ); document.write( "(1-x^2) = 0 \n" ); document.write( "(1-x)(1+x) = 0 \n" ); document.write( "x = 1 or x = -1 \n" ); document.write( "--- \n" ); document.write( "Checking: \n" ); document.write( "log(-x)= -log(x) \n" ); document.write( "Can x = 1 ? \n" ); document.write( "log(-1) = -log(1) \n" ); document.write( "No \n" ); document.write( "------ \n" ); document.write( "Can x = -1 ? \n" ); document.write( "log(1) = -log(-1) \n" ); document.write( "No \n" ); document.write( "------------- \n" ); document.write( "Conclusion: No solution. \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |