document.write( "Question 599021: log(-x)=-log(x) \n" ); document.write( "
Algebra.Com's Answer #378771 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log(-x)=-log(x)
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\n" ); document.write( "log(-x)+log(x) = 0
\n" ); document.write( "--
\n" ); document.write( "log[(-x)(x)] = 0
\n" ); document.write( "--
\n" ); document.write( "-x^2 = 10^0
\n" ); document.write( "---
\n" ); document.write( "-x^2 = 1
\n" ); document.write( "(1-x^2) = 0
\n" ); document.write( "(1-x)(1+x) = 0
\n" ); document.write( "x = 1 or x = -1
\n" ); document.write( "---
\n" ); document.write( "Checking:
\n" ); document.write( "log(-x)= -log(x)
\n" ); document.write( "Can x = 1 ?
\n" ); document.write( "log(-1) = -log(1)
\n" ); document.write( "No
\n" ); document.write( "------
\n" ); document.write( "Can x = -1 ?
\n" ); document.write( "log(1) = -log(-1)
\n" ); document.write( "No
\n" ); document.write( "-------------
\n" ); document.write( "Conclusion: No solution.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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