document.write( "Question 598841: a group of students decided to purchase a tv ranging from 170 to 195 $. but at the last moment, two students backed out of the decision so that the remaining students had to pay 10 $. more than they had planned. find the cost of the tv if the amount has been shared equally among the students. \n" ); document.write( "
Algebra.Com's Answer #378738 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a group of students decided to purchase a tv ranging from 170 to 195 $. \n" ); document.write( " but at the last moment, two students backed out of the decision so that the remaining students had to pay 10 $. more than they had planned. \n" ); document.write( " find the cost of the tv if the amount has been shared equally among the students. \n" ); document.write( ": \n" ); document.write( "Let c = cost of the TV \n" ); document.write( "Let s = original number of students \n" ); document.write( "then \n" ); document.write( "(s-2) = actual number of students that paid \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply by s(s-2), clear the denominators, results: \n" ); document.write( "cs - c(s-2) = 10s(s-2) \n" ); document.write( "cs - cs + 2c = 10s^2 - 20s \n" ); document.write( "2c = 10s^2 - 20s \n" ); document.write( "divide eq by 2 \n" ); document.write( "c = 5s^2 - 10s \n" ); document.write( "We know that c has to be between 170 and 195 \n" ); document.write( "A little substitution for s reveals that only value for c is $175, when s=7 (original number students) \n" ); document.write( ": \n" ); document.write( "Check this actual number students are 5 \n" ); document.write( "175/5 = $35 \n" ); document.write( "175/7 = $25 \n" ); document.write( " |