document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=598721>Question 598721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> &#8730;(x^2-x)+7=2(x^2-x)-1<BR>\n" );
document.write( "The first part is all in the square root.<BR>\n" );
document.write( "I cannot get the answer at all. I keep comming up with no solution but my teacher says its not right. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378687 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> &#8730;(x^2-x)+7=2(x^2-x)-1<BR>\n" );
document.write( "let u=(x^2-x)<BR>\n" );
document.write( "&#8730;(u+7)=2u-1<BR>\n" );
document.write( "square both sides<BR>\n" );
document.write( "u+7=4u^2-4u+1<BR>\n" );
document.write( "4u^2-5u-6=0<BR>\n" );
document.write( "(4u+3)(u-2)=0<BR>\n" );
document.write( "..<BR>\n" );
document.write( "4u+3=0<BR>\n" );
document.write( "u=-3/4<BR>\n" );
document.write( "x^2-x=3/4<BR>\n" );
document.write( "LCD:4<BR>\n" );
document.write( "4x^2-4x=3<BR>\n" );
document.write( "4x^2-4x-3=0<BR>\n" );
document.write( "(2x-3)(2x+1)=0<BR>\n" );
document.write( "x=3/2<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=-1/2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "u-2=0<BR>\n" );
document.write( "u=2<BR>\n" );
document.write( "x^2-x=2<BR>\n" );
document.write( "x^2-x-2=0<BR>\n" );
document.write( "(x-2)(x+1)=0<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=-1<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Note: 3/2 and -1/2 may be extraneous roots because we squared both sides. The original is a second degree equation which is only supposed to have 2 roots. You should check by plugging all four roots into the original equation and see which two works.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );