document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=598397>Question 598397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> &#8730;3X+15=x+3<BR>\n" );
document.write( "&#8730;3X+15^2=(x+3)^2<BR>\n" );
document.write( "3x+15=(x+3)^2<BR>\n" );
document.write( "3x+15=x^2+6x+9<BR>\n" );
document.write( "-15 -15<BR>\n" );
document.write( "3x=x^2+6x-6<BR>\n" );
document.write( "-3x -3x<BR>\n" );
document.write( "0=x^2+3x-6 <BR>\n" );
document.write( "having trouble factoring x^2+3x-6 <BR>\n" );
document.write( "thanks so much  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378673 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Everything you did here looks right but;<BR>\n" );
document.write( "x^2 + 3x - 6 = 0; will not factor, you have to use the quadratic formula;<BR>\n" );
document.write( "solution would be x ~ -4.37 and x ~ +1.37, however only +1.37 would be a solution in the original problem<BR>\n" );
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