document.write( "Question 598639: A tugboat goes 180 miles upstream in 15 hours. The return trip downstream takes 10 hours. Find the speed of the tugboat wihtout a current and the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #378646 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A tugboat goes 180 miles upstream in 15 hours. The return trip downstream takes 10 hours. Find the speed of the tugboat wihtout a current and the speed of the current. \n" ); document.write( "-------------------------- \n" ); document.write( "Upstream DATA: \n" ); document.write( "distance = 180 miles ; time = 15 hrs ; rate = 180/15 = 12 mph \n" ); document.write( "----- \n" ); document.write( "Downstream DATA: \n" ); document.write( "distance = 180 miles ; time = 10 hrs ; rate = 180/10 = 18 mph \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "Upstream: b - c = 12 mph \n" ); document.write( "Downstrm: b + c = 18 mph \n" ); document.write( "------------------------------ \n" ); document.write( "Add and solve for \"b\": \n" ); document.write( "2b = 30 mph \n" ); document.write( "b = 15 mph (boat speed in still water) \n" ); document.write( "--- \n" ); document.write( "Solve for \"c\": \n" ); document.write( "b + c = 18 mph \n" ); document.write( "15 + c = 18 \n" ); document.write( "c = 3 mph (speed of the current) \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " |