document.write( "Question 598503: log 3x= log4 + log(x-3) \n" ); document.write( "
Algebra.Com's Answer #378612 by nerdybill(7384)\"\" \"About 
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log 3x= log4 + log(x-3)
\n" ); document.write( "log 3x= log 4(x-3)
\n" ); document.write( "3x= 4(x-3)
\n" ); document.write( "3x= 4x-12
\n" ); document.write( "0 = x-12
\n" ); document.write( "12 = x\r
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