document.write( "Question 598503: log 3x= log4 + log(x-3) \n" ); document.write( "
Algebra.Com's Answer #378612 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! log 3x= log4 + log(x-3) \n" ); document.write( "log 3x= log 4(x-3) \n" ); document.write( "3x= 4(x-3) \n" ); document.write( "3x= 4x-12 \n" ); document.write( "0 = x-12 \n" ); document.write( "12 = x\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |