document.write( "Question 598457: Find all the solutions t in the interval (0, 2pi) to the equation
\n" ); document.write( " sin (2t) = sqare root 2 cos (t)
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Algebra.Com's Answer #378588 by lwsshak3(11628)\"\" \"About 
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Find all the solutions t in the interval (0, 2pi) to the equation
\n" ); document.write( "sin (2t) = sqare root 2 cos (t)
\n" ); document.write( "2sintcost=√2cost
\n" ); document.write( "2sintcost-√2cost=0
\n" ); document.write( "cost(2sint-√2)=0
\n" ); document.write( "cost=0
\n" ); document.write( "t=π/2 and 3π/2
\n" ); document.write( "or
\n" ); document.write( "2sint-√2=0
\n" ); document.write( "sint=√2/2
\n" ); document.write( "t=π/4 and 3π/4 (in quadrants I and II where sin>0)
\n" ); document.write( "..
\n" ); document.write( "solutions: π/4, π/2, 3π/4 and 3π/2
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