document.write( "Question 598439: Direction: Write an equation for each hyperbola. \r
\n" ); document.write( "\n" ); document.write( "vertices: (1,-1) and (1,-9)
\n" ); document.write( "conjugate axis of length 6units\r
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\n" ); document.write( "\n" ); document.write( "I would like to say please and thank you for helping me, in advance.(:
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Algebra.Com's Answer #378584 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Direction: Write an equation for each hyperbola.
\n" ); document.write( "vertices: (1,-1) and (1,-9)
\n" ); document.write( "conjugate axis of length 6units
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\n" ); document.write( "This is a hyperbola with vertical transverse axis.
\n" ); document.write( "Its standard form of equation: (y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of center.
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "x-coordinate of center=1
\n" ); document.write( "y-coordinate of center=(-1+(-9))/2=-10/2=-5 (by midpoint formula)
\n" ); document.write( "center: (1,-5)
\n" ); document.write( "length of vertical transverse axis=8 (-1 to -9)=2a
\n" ); document.write( "a=4
\n" ); document.write( "a^2=16
\n" ); document.write( "given length of conjugate axis=6=2b
\n" ); document.write( "b=3
\n" ); document.write( "b^2=9
\n" ); document.write( "Equation:
\n" ); document.write( "(y+5)^2/16-(x-1)^2/9=1
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