document.write( "Question 598439: Direction: Write an equation for each hyperbola. \r
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document.write( "vertices: (1,-1) and (1,-9)
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document.write( "conjugate axis of length 6units\r
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document.write( "I would like to say please and thank you for helping me, in advance.(: \n" );
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Algebra.Com's Answer #378584 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Direction: Write an equation for each hyperbola. \n" ); document.write( "vertices: (1,-1) and (1,-9) \n" ); document.write( "conjugate axis of length 6units \n" ); document.write( "** \n" ); document.write( "This is a hyperbola with vertical transverse axis. \n" ); document.write( "Its standard form of equation: (y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of center. \n" ); document.write( "For given hyperbola: \n" ); document.write( "x-coordinate of center=1 \n" ); document.write( "y-coordinate of center=(-1+(-9))/2=-10/2=-5 (by midpoint formula) \n" ); document.write( "center: (1,-5) \n" ); document.write( "length of vertical transverse axis=8 (-1 to -9)=2a \n" ); document.write( "a=4 \n" ); document.write( "a^2=16 \n" ); document.write( "given length of conjugate axis=6=2b \n" ); document.write( "b=3 \n" ); document.write( "b^2=9 \n" ); document.write( "Equation: \n" ); document.write( "(y+5)^2/16-(x-1)^2/9=1 \n" ); document.write( " \n" ); document.write( " |