document.write( "Question 598261:  4^x - (17 times 2^x) + 16 = 0 (let me read it to make sure: 4 raised to the x power minus 17 times 2 raised to the x power plus 16 equals zero). \n" ); document.write( "
Algebra.Com's Answer #378550 by ankor@dixie-net.com(22740)\"\" \"About 
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\"4%5Ex+-+17%282%5Ex%29+%2B+16\" = 0
\n" ); document.write( "4 = 2 squared, therefore we can write it
\n" ); document.write( "\"2%5E%282x%29+-+17%282%5Ex%29+%2B+16\" = 0
\n" ); document.write( "This looks like a quadratic equation where 2^x takes the place of x, factors to:
\n" ); document.write( "\"%282%5Ex+-+16%29%282%5Ex+-1%29\" = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "2^x = 1
\n" ); document.write( "2^0 = 1
\n" ); document.write( "therefore
\n" ); document.write( "x = 0
\n" ); document.write( "and
\n" ); document.write( "2^x = 16
\n" ); document.write( "2^4 = 16
\n" ); document.write( "therefore
\n" ); document.write( "x = 4
\n" ); document.write( ":
\n" ); document.write( "Check this by replacing x with 4 in the original equation
\n" ); document.write( "\"4%5E4+-+17%282%5E4%29+%2B+16\" = 0
\n" ); document.write( "256 - 17(16) + 16 =
\n" ); document.write( "256 - 272 + 16 = 0
\n" ); document.write( ":
\n" ); document.write( "Do the same for x=0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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