document.write( "Question 598315: I need help factoring out this problem\"20x%5E3%2B16x%5E2%2B25x%2B20=0\"
\n" ); document.write( "I did it in two group
\n" ); document.write( "(20x^3+16x^2) (25x+20)=0
\n" ); document.write( "4x^2(5x+4) 5(5x+4)=0
\n" ); document.write( "(5x+4) (4x^2+5)=0
\n" ); document.write( "5x+4=0
\n" ); document.write( "5x+4-4=0-4
\n" ); document.write( "5x=-4
\n" ); document.write( "divide x= -4/5
\n" ); document.write( "I could not factor out (4x^2+5)=0
\n" ); document.write( "

Algebra.Com's Answer #378549 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You are correct. You cannot factor \"4x%5E2%2B5\". So you simply solve for x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x%5E2%2B5=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x%5E2=-5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2=-5%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%22%22%2B-sqrt%28-5%2F4%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now if you haven't learned about complex/imaginary numbers yet, then you would ignore this (and the rest of the solution) and simply say that the only solution is \"x=-4%2F5\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "However, if you have learned about complex/imaginary numbers, then...\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%22%22%2B-sqrt%28-5%2F4%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%28i%2Asqrt%285%29%29%2F2\" or \"x=-%28i%2Asqrt%285%29%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So if you have learned about complex/imaginary numbers, then there are three solutions and they are \"x=-4%2F5\", \"x=%28i%2Asqrt%285%29%29%2F2\" or \"x=-%28i%2Asqrt%285%29%29%2F2\"
\n" ); document.write( "
\n" );