document.write( "Question 598274: The perimeter of a rectangular painting is 290 centimeters. If the width of the painting is 62 centimeters, what is its length? \n" ); document.write( "
Algebra.Com's Answer #378530 by math-vortex(648)![]() ![]() You can put this solution on YOUR website! Hi, there-- \n" ); document.write( ". \n" ); document.write( "The PERIMETER P is the distance around the rectangle. \n" ); document.write( ". \n" ); document.write( "Let's call the width of the rectangle W and the length of the rectangle L. \n" ); document.write( ". \n" ); document.write( "As you go around the edge there two equal lengths and two equal widths. The formula for the perimeter of a rectangle is P=2*L+2*W. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Substitute 290 for P and 62 for the width. \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Solve for L. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The equation L=83 means that the length is 83 cm. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "CHECK your work. \n" ); document.write( "2(62)+2(83) = 124+166 = 290cm. \n" ); document.write( ". \n" ); document.write( "The length of the rectangle is 83cm. \n" ); document.write( ". \n" ); document.write( "That's it! Feel free to email via gmail if the solution is unclear. \n" ); document.write( ". \n" ); document.write( "Ms.Figgy \n" ); document.write( "math.in.the.vortex@gmail.com \n" ); document.write( " |