document.write( "Question 598274: The perimeter of a rectangular painting is 290 centimeters. If the width of the painting is 62 centimeters, what is its length? \n" ); document.write( "
Algebra.Com's Answer #378530 by math-vortex(648)\"\" \"About 
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Hi, there--
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\n" ); document.write( "The PERIMETER P is the distance around the rectangle.
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\n" ); document.write( "Let's call the width of the rectangle W and the length of the rectangle L.
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\n" ); document.write( "As you go around the edge there two equal lengths and two equal widths. The formula for the perimeter of a rectangle is P=2*L+2*W.
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\n" ); document.write( "\"P=2L%2B2W\"
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\n" ); document.write( "Substitute 290 for P and 62 for the width.
\n" ); document.write( "\"290=2L%2B2%2862%29\"
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\n" ); document.write( "Solve for L.
\n" ); document.write( "\"290=2L%2B2%2862%29\"
\n" ); document.write( "\"290=2L%2B124\"
\n" ); document.write( "\"290-124=2L\"
\n" ); document.write( "\"2L=166\"
\n" ); document.write( "\"L=83\"
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\n" ); document.write( "The equation L=83 means that the length is 83 cm.
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\n" ); document.write( "CHECK your work.
\n" ); document.write( "2(62)+2(83) = 124+166 = 290cm.
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\n" ); document.write( "The length of the rectangle is 83cm.
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\n" ); document.write( "That's it! Feel free to email via gmail if the solution is unclear.
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\n" ); document.write( "Ms.Figgy
\n" ); document.write( "math.in.the.vortex@gmail.com
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