document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=598197>Question 598197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider a binomial experiment with 20 trials and probability 0.45 on a single trial. Use an approximatation to the normal distribution to find the probability of exactly 10 successes. Round your answer to the thousandths place.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378494 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consider a binomial experiment with 20 trials and probability 0.45 on a single trial. Use an approximatation to the normal distribution to find the probability of exactly 10 successes. Round your answer to the thousandths place. <BR>\n" );
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document.write( "u = np = 20*0.45 = 9<BR>\n" );
document.write( "s = sqrt(npq) = sqrt(9*0.55) = 2.22<BR>\n" );
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document.write( "z(9.5) = (9.5-9)/[2.22/sqrt(20) = 1.007<BR>\n" );
document.write( "z(10.5) = (10.5-9)/[2.22/sqrt(20)] = 3.0217<BR>\n" );
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document.write( "P(x = 10) ~ P(1.007< z < 3.0217) = 0.1557<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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