document.write( "Question 598194: 1. Joan has $3.50 in nickels, dimes and quarters. SHe has the same number of nickels as quarters. She has twice as many nickels and dime. \r
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\n" ); document.write( "\n" ); document.write( "2. Cooper has some nickels, twice as many dimes as nickels and half as many quarters as nickels. He has less than $1.00. How much money does Cooper have?\r
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Algebra.Com's Answer #378483 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If he had 4 quarters, that would be $1 already without consideration of the nickels and dimes.\r
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\n" ); document.write( "\n" ); document.write( "If he had 3 quarters (75 cents) then he would have 6 nickels (30 cents) and again, we are over a buck.\r
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\n" ); document.write( "\n" ); document.write( "If he had 2 quarters (50 cents then he would have 4 nickels (20 cents). Still less than a buck, but then he would have 8 dimes -- too much again.\r
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\n" ); document.write( "\n" ); document.write( "If he had 0 quarters, then he would have zero nickels and zero dimes. But the probem states that he has \"some\" nickels, that is more than zero nickels.\r
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\n" ); document.write( "\n" ); document.write( "The only possibility left is 1 quarter, 2 nickels, and 4 dimes for a total of 75 cents.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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