document.write( "Question 598032: It takes a passenger train 5hrs less time than it takes a freight train to make the trip from Ellettsville to Fairland. The passenger train averages 72km/h, while While freight train averages 36km/h.
\n" ); document.write( "Find the distance from Ellettsville to Fairland.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Please help.
\n" ); document.write( "

Algebra.Com's Answer #378471 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
It takes a passenger train 5hrs less time than it takes a freight train to make the trip from Ellettsville to Fairland.
\n" ); document.write( " The passenger train averages 72km/h, while freight train averages 36km/h.
\n" ); document.write( "Find the distance from Ellettsville to Fairland.
\n" ); document.write( ":
\n" ); document.write( "First find the times required
\n" ); document.write( "t = Pass train time
\n" ); document.write( "(t+5) = Freight time
\n" ); document.write( ":
\n" ); document.write( "Both trains went the same distance
\n" ); document.write( "Write a dist equation: dist = speed * time
\n" ); document.write( "72t = 36(t+5)
\n" ); document.write( "72t = 36t + 180
\n" ); document.write( "72t - 36t = 180
\n" ); document.write( "36t = 180
\n" ); document.write( "t = 5 hrs
\n" ); document.write( ":
\n" ); document.write( "Find the distance from E to F
\n" ); document.write( "5 * 72 = 360 mi
\n" ); document.write( ":
\n" ); document.write( "Check the distance, (freight time = 10 hrs)
\n" ); document.write( "10 * 36 = 360 mi
\n" ); document.write( ":
\n" ); document.write( "
\n" ); document.write( "
\n" );