document.write( "Question 598032: It takes a passenger train 5hrs less time than it takes a freight train to make the trip from Ellettsville to Fairland. The passenger train averages 72km/h, while While freight train averages 36km/h.
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document.write( "Find the distance from Ellettsville to Fairland.\r
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document.write( "Please help. \n" );
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Algebra.Com's Answer #378471 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! It takes a passenger train 5hrs less time than it takes a freight train to make the trip from Ellettsville to Fairland. \n" ); document.write( " The passenger train averages 72km/h, while freight train averages 36km/h. \n" ); document.write( "Find the distance from Ellettsville to Fairland. \n" ); document.write( ": \n" ); document.write( "First find the times required \n" ); document.write( "t = Pass train time \n" ); document.write( "(t+5) = Freight time \n" ); document.write( ": \n" ); document.write( "Both trains went the same distance \n" ); document.write( "Write a dist equation: dist = speed * time \n" ); document.write( "72t = 36(t+5) \n" ); document.write( "72t = 36t + 180 \n" ); document.write( "72t - 36t = 180 \n" ); document.write( "36t = 180 \n" ); document.write( "t = 5 hrs \n" ); document.write( ": \n" ); document.write( "Find the distance from E to F \n" ); document.write( "5 * 72 = 360 mi \n" ); document.write( ": \n" ); document.write( "Check the distance, (freight time = 10 hrs) \n" ); document.write( "10 * 36 = 360 mi \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |