document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=598011>Question 598011</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x.\r<BR>\n" );
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document.write( "log base 6 of (3x+14) - log base 6 of 5 = log base 6 of (2x)\r<BR>\n" );
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document.write( "(I have gotten it down to log base 6 of (3x+14)- log base 6 of (2x) - log base 6 of 5 = 0 and I know that you need to divide the logs next, but the 3 logs are tripping me up and I cannot figure out how to simplify it correctly.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378423 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x. <BR>\n" );
document.write( "log base 6 of (3x+14) - log base 6 of 5 = log base 6 of (2x) <BR>\n" );
document.write( "log6(3x+14)-log6(5)=log6(2x)<BR>\n" );
document.write( "log6(3x+14)-log6(5)-log6(2x)=0<BR>\n" );
document.write( "log6(3x+14)-(log6(5)+log6(2x))=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log6[(3x+14)/(5*2x)]=0<BR>\n" );
document.write( "log6[(3x+14)/(10x)]=0<BR>\n" );
document.write( "convert to exponential form: base(6) raised to log of number(0)=number(3x+14)/(10x)<BR>\n" );
document.write( "6^0=(3x+14)/(10x)=1<BR>\n" );
document.write( "10x=3x+14<BR>\n" );
document.write( "7x=14<BR>\n" );
document.write( "x=2<BR>\n" );
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