document.write( "Question 597966: Solve:\r
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document.write( "2-(the absolute value of (4-3x)) > greater than or equal to =-7 \r
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document.write( "2-|4-3x|≥-7 (hope this format helps)\r
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document.write( "THANKS SOO MUCH! \n" );
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Algebra.Com's Answer #378412 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 2-|4-3x|≥-7 \n" ); document.write( "solve for 2 conditions \n" ); document.write( "a.)2-(4-3x)≥-7 \n" ); document.write( "2-4+3x≥-7 \n" ); document.write( "-2+3x≥-7 \n" ); document.write( "3x≥-5 \n" ); document.write( "x≥-5/3 \n" ); document.write( ".. \n" ); document.write( "b.) 2-(-4+3x)≥-7 \n" ); document.write( "2+4-3x≥-7 \n" ); document.write( "6-3x≥-7 \n" ); document.write( "-3x≥-13 \n" ); document.write( "divide both sides by -3 and reverse inequality sign \n" ); document.write( "x≤13/3 \n" ); document.write( "numberl line: \n" ); document.write( "<........[-5/3<====>13/3]............> \n" ); document.write( "solution: [-5/3,13/3] \n" ); document.write( " |