document.write( "Question 597877: I am trying to finish a problem where I am multiplying rational expressions. This is what I have simplified it down to: (c-1)*(2c+1)/(c^(2)-1). I know I must factor out (c-1) and (c^(2)-1) and the greatest common factor is (c-1). I have used algebra.com's solver and I know the answer is (2c+1)/(c+1). But how do I get (c+1) from factoring (c^(2)-1) by (c-1)? Thank you! \n" ); document.write( "
Algebra.Com's Answer #378375 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"c%5E2-1\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28c%29%5E2-%281%29%5E2\" Rewrite \"1\" as \"%281%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "Notice how we have a difference of squares \"A%5E2-B%5E2\" where in this case \"A=c\" and \"B=1\".\r
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\n" ); document.write( "\n" ); document.write( "So let's use the difference of squares formula \"A%5E2-B%5E2=%28A%2BB%29%28A-B%29\" to factor the expression:\r
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\n" ); document.write( "\n" ); document.write( "\"A%5E2-B%5E2=%28A%2BB%29%28A-B%29\" Start with the difference of squares formula.\r
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\n" ); document.write( "\n" ); document.write( "\"%28c%29%5E2-%281%29%5E2=%28c%2B1%29%28c-1%29\" Plug in \"A=c\" and \"B=1\".\r
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\n" ); document.write( "\n" ); document.write( "So this shows us that \"c%5E2-1\" factors to \"%28c%2B1%29%28c-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words \"c%5E2-1=%28c%2B1%29%28c-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Hopefully this helps. If not, let me know.
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