document.write( "Question 597704: Write the equation of a hyperbola with vertices at (1,1) and (9,1) and foci at (0,1)and (10,1). \n" ); document.write( "
Algebra.Com's Answer #378299 by lwsshak3(11628)\"\" \"About 
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Write the equation of a hyperbola with vertices at (1,1) and (9,1) and foci at (0,1)and (10,1).
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\n" ); document.write( "Standard form of equation for a hyperbola with horizontal transverse axis:
\n" ); document.write( "(x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "x-coordinate of center=(9+1)/2=5 (use midpoint formula)
\n" ); document.write( "y-coordinate of center=1
\n" ); document.write( "center: (5,1)\r
\n" ); document.write( "\n" ); document.write( "length of horizontal transverse axis=8 (from 1 to 9)=2a
\n" ); document.write( "a=4
\n" ); document.write( "a^2=16
\n" ); document.write( "..
\n" ); document.write( "Foci
\n" ); document.write( "2c=9 ( from 1 to 10)
\n" ); document.write( "c=4.5
\n" ); document.write( "..
\n" ); document.write( "c^2=a^2+b^2
\n" ); document.write( "b^2=c^2-a^2=20.25-16=4.25
\n" ); document.write( "..
\n" ); document.write( "Equation of hyperbola:
\n" ); document.write( "(x-5)^2/16-(y-1)^2/4.25=1
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