document.write( "Question 597522: I'm so lost on parabola and hyperbola and don't know where to start on these problems \r
\n" ); document.write( "\n" ); document.write( "1) (y-3)^2-4(x-4)^2=16\r
\n" ); document.write( "\n" ); document.write( "it is asking for the standard form of this equation, center, vertices, foci ,asymptotes
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Algebra.Com's Answer #378290 by lwsshak3(11628)\"\" \"About 
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(y-3)^2-4(x-4)^2=16
\n" ); document.write( "it is asking for the standard form of this equation, center, vertices, foci ,asymptotes
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\n" ); document.write( "(y-3)^2-4(x-4)^2=16
\n" ); document.write( "divide by16
\n" ); document.write( "(y-3)^2/16-(x-4)^2/4=1
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis (y-term comes first) of the standard form: (y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given equation:(y-3)^2/16-(x-4)^2/4=1
\n" ); document.write( "center: (4,3)
\n" ); document.write( "a^2=16
\n" ); document.write( "a=√16=4
\n" ); document.write( "b^2=4
\n" ); document.write( "b=√4=2
\n" ); document.write( "c^2=a^2+b^2=16+4=20
\n" ); document.write( "c=√20≈4.5
\n" ); document.write( "..
\n" ); document.write( "vertices: (4,3±a)=(4,3±4)=(4,-1) and (4,7)
\n" ); document.write( "foci: (4,3±c)=(4,3±4.5)=(4,-1.5) and (4,7.5)
\n" ); document.write( "..
\n" ); document.write( "Asymptotes are straight lines of the standard form y=mx+b, m=slope, b=y-intercept.
\n" ); document.write( "Asymptotes also go thru the center.
\n" ); document.write( "slope of asymptotes=±a/b=±4/2=±2
\n" ); document.write( "Equations of asymptotes:
\n" ); document.write( "y=2x+b
\n" ); document.write( "solving for b using coordinates of center which are on the line
\n" ); document.write( "3=2*4+b
\n" ); document.write( "b=-5
\n" ); document.write( "equation: y=2x-5
\n" ); document.write( "..
\n" ); document.write( "y=-2x+b
\n" ); document.write( "solving for b using coordinates of center which are on the line
\n" ); document.write( "3=-2*4+b
\n" ); document.write( "b=11
\n" ); document.write( "equation: y=-2x+11\r
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