document.write( "Question 597564: The perimeter of a rectangle is 72\". You know the lenght is 8 times bigger than the width. What are the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #378236 by Babyy_Girl2012(2) $\"\"$ $\"About$

You can put this solution on YOUR website!
So, as you know in a rectangle, there are 2 pairs of congruent sides. Meaning, the top and bottom are equally the same measurement. Same goes for the two sides. You know two things. The perimeter is equal to 72\" and the length is 8 times bigger than the width. For perimeter, you add the measurements of all sides. I, personally would start off by making the width even numbers.
\n" ); document.write( "For example: Let's say the width was 2\". 2x8=16. From there, you would add 16+16+2+2. That only equals 36. So, then you could go to the next even up, which is 4. 4x8=32. Therefore, you'd add 32+32+4+4. That equals 72\". That is what you needed. Your answer is : 4;4;32;32 \n" ); document.write( "

\n" );