document.write( "Question 597531: Sin^2 x= cos^2 x for 0 degrees less than or equal to x which is less than 360 degrees\r
\n" ); document.write( "\n" ); document.write( "I don't understand this problem at all and I am having trouble even being able to find it in my text book. If you could help me solve for x on this one, I think it would help me be able to better understand how to do it. Then, I will also have an example to look back on when working on other similar problems. Thank you for your time and help!
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Algebra.Com's Answer #378233 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Sin^2 x= cos^2 x for 0 degrees less than or equal to x which is less than 360 degrees
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\n" ); document.write( "Sin^2 x= cos^2 x 0 <= x < 360
\n" ); document.write( "Sub (1 - sin^2) for cos^2
\n" ); document.write( "sin^2 = 1 - sin^2
\n" ); document.write( "2sin^2 = 1
\n" ); document.write( "sin^2 = 1/2
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\n" ); document.write( "sin = -sqrt(2)/2, +sqrt(2)/2
\n" ); document.write( "x = 45 degs, 135 degs, 225 degs, 315 degs
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