document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=597503>Question 597503</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 2 cm greater than twice its width. The area of the rectangle is 40 cm^2. find the dimensions of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378224 by </B><A HREF=/tutors/aboutme.mpl?userid=ExplanationCentral><B>ExplanationCentral(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ExplanationCentral><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ExplanationCentral><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length be l and the width be w.<BR>\n" );
document.write( "So we have l = 2w + 2. <BR>\n" );
document.write( "The area of the rectangle = length*width = (2w+2)*w = 2w^2 + 2w = 40<BR>\n" );
document.write( "Solving this quadratic equation, we get w = 4 cm. This means the length = 2(4) + 2 = 10.<BR>\n" );
document.write( "So width = 4 and length = 10. </SPAN>\n" );
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