document.write( "Question 597464: Write the standard form of the equation of the circle with raduis \"sqrt%2813%29\" and whose center is the orgin. \n" ); document.write( "
Algebra.Com's Answer #378214 by math-vortex(648)\"\" \"About 
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Hi, there--
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\n" ); document.write( "The form for the equation for a circle in standard form is
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\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"
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\n" ); document.write( "where
\n" ); document.write( "(h,k)=(0,0) is the center of the circle and r = sqrt(13) is the radius.
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\n" ); document.write( "Substitute your values for the center and radius of the circle into the equation.
\n" ); document.write( "\"%28x-0%29%5E2%2B%28y-0%29%5E2=%28sqrt%2813%29%29%5E2\"
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\n" ); document.write( "Simplify.
\n" ); document.write( "\"x%5E2%2By%5E2=13\"
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\n" ); document.write( "That's it. Feel free to email me via gmail if the explanation is unclear.
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\n" ); document.write( "Ms.Figgy
\n" ); document.write( "matth.in.the.vortex@gmail.com
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