document.write( "Question 597441: How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution? \n" ); document.write( "

Algebra.Com's Answer #378193 by edjones(8007) $\"\"$ $\"About$

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6*.2=1.2 total gal of acid.
\n" ); document.write( "Let x=gal of pure acid required.
\n" ); document.write( "x*1.00=x total gal of acid
\n" ); document.write( "(6+x)*0.9=.9(6+x) total gal acid
\n" ); document.write( ".
\n" ); document.write( "1.2+x=.9(6+x)
\n" ); document.write( "1.2+x=5.4+.9x
\n" ); document.write( ".1x=4.2
\n" ); document.write( "x=42 gallons
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\n" ); document.write( "Ed \n" ); document.write( "

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