document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=597423>Question 597423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Calculate the number of sides of a regular polygon in which the exterior angle os one - fifth of the interior angle. Please show working. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378165 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Calculate the number of sides of a regular polygon in which the exterior angle is one - fifth of the interior angle. Please show working.<BR>\n" );
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document.write( "Let the interior angle be \"x\"<BR>\n" );
document.write( "Then the exterior angle is \"x/5\"<BR>\n" );
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document.write( "Equation: <BR>\n" );
document.write( "x + x/5 = 180 degrees<BR>\n" );
document.write( "(6/5)x = 180<BR>\n" );
document.write( "(1/5)x = 30 degrees<BR>\n" );
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document.write( "Note: The sum of all the exterior angle = 360.<BR>\n" );
document.write( "# of exterior angles = 360/30 = 12<BR>\n" );
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document.write( "Therefore # of sides = 12<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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