document.write( "Question 597336: In ten years from now, a father will be twice as old as his son. Ten years ago, he was 6 times as old. How old are they now? \n" ); document.write( "

Algebra.Com's Answer #378139 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+f+\"$ = Father's age now
\n" ); document.write( "Let $\"+s+\"$ = Son's age now
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"+f+%2B+10+=+2%2A%28+s+%2B+10+%29+\"$
\n" ); document.write( "(2) $\"+f+-+10+=+6%2A%28+s+-+10+%29+\"$
\n" ); document.write( "------------------------
\n" ); document.write( "(1) $\"+f+%2B+10+=+2s+%2B+20+\"$
\n" ); document.write( "(1) $\"+f+-+2s+=+10+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+f+-+10+=+6s+-+60+\"$
\n" ); document.write( "(2) $\"+f+-+6s+=+-50+\"$
\n" ); document.write( "Subtract (2) from (1)
\n" ); document.write( "(1) $\"+f+-+2s+=+10+\"$
\n" ); document.write( "(2) $\"+-f+%2B+6s+=+50+\"$
\n" ); document.write( " $\"+4s+=+60+\"$
\n" ); document.write( " $\"+s+=+15+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+f+-+2s+=+10+\"$
\n" ); document.write( "(1) $\"+f+-+2%2A15+=+10+\"$
\n" ); document.write( "(1) $\"+f+-+30+=+10+\"$
\n" ); document.write( "(1) $\"+f+=+40+\"$
\n" ); document.write( "The father is 40
\n" ); document.write( "The Son is 15
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+40+%2B+10+=+2%2A%28+15+%2B+10+%29+\"$
\n" ); document.write( "(1) $\"+50+=+2%2A25+\"$
\n" ); document.write( "(1) $\"+50+=+50+\"$
\n" ); document.write( "(2) $\"+40+-+10+=+6%2A%28+15+-+10+%29+\"$
\n" ); document.write( "(2) $\"+30+=+6%2A5+\"$
\n" ); document.write( "(2) $\"+30+=+30+\"$
\n" ); document.write( "OK \n" ); document.write( "

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