document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=597082>Question 597082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a certain metal is 40% tin.  how many kilograms of this metal must be mixed with 80 kilograms of a metal that is 70% tin to get a metal that is 50% tin? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #378086 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=378086\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A certain metal is 40% tin.<BR>\n" );
document.write( " How many kilograms of this metal must be mixed with 80 kilograms of a metal that is 70% tin to get a metal that is 50% tin?<BR>\n" );
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document.write( "let x = amt of 40% tin\r<BR>\n" );
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document.write( "A typical mixture equation<BR>\n" );
document.write( ".40x + .70(80) = .50(x+80)<BR>\n" );
document.write( ".40x + 56 = .50x + 40<BR>\n" );
document.write( "56 - 40 = .50x - .40x<BR>\n" );
document.write( "16 = .10x<BR>\n" );
document.write( "x = 16/.1<BR>\n" );
document.write( "x = 160 km of 40% tin required<BR>\n" );
document.write( " </SPAN>\n" );
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