document.write( "Question 597170: I'm doing homework and I wasn't able to get to class because I was out of town. I have the worksheet, it tells me to Use the CHANGE OF BASE formula to evaluate the following.\r
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\n" ); document.write( "\n" ); document.write( "Most of the problems are like this. I looked at examples online, but none of the examples are set up like this.\r
\n" ); document.write( "\n" ); document.write( "What I have been doing is just setting the problem up differently for example Log2 (10)=x would be 10=2^x and I'm really really confused. I need help. Please someone respond.\r
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Algebra.Com's Answer #378043 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The change of base formula is:\r\n" );
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document.write( "\"log%28B%2CU%29\" = \"log%28U%29%2Flog%28B%29\"\r\n" );
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document.write( "or\r\n" );
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document.write( "\"log%28B%2CU%29\" = \"ln%28U%29%2Fln%28B%29\"\r\n" );
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document.write( "Therefore\r\n" );
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document.write( "\"log%282%2C10%29\"= x = \"log%282%29%2Flog%2810%29\" =\".3010299957%2F1\" = .3010299957   \r\n" );
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document.write( "or you can use:\r\n" );
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document.write( "\"log%282%2C10%29\" = x = \"ln%282%29%2Fln%2810%29\" =\".6931471806%2F2.302585093\" = .3010299957 = .3010299957  \r\n" );
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document.write( "Log12 (1243)=x\r\n" );
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document.write( "\"log%2812%2C1243%29\" = x = \"log%281243%29%2Flog%2812%29\" =\"3.094471129%2F1.079181246\" = 2.867424856   \r\n" );
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document.write( "or you can use:\r\n" );
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document.write( "\"log%2812%2C1243%29\" = x = \"ln%281243%29%2Fln%2812%29\" =\"7.125283092%2F2.48490665\" = 2.867424856\r\n" );
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document.write( "Notice that you may use either \"log\" (which is base 10) or \"ln\" (which is\r\n" );
document.write( "base \"e\").  Both are on your calculator.  The numbers you divide will be\r\n" );
document.write( "different but when you divide them you will always get the same answer either way.\r\n" );
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document.write( "Edwin
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