document.write( "Question 596729: Hi!
\n" ); document.write( "I have a homework that says:
\n" ); document.write( "solve the following quadratic equations by factoring. \r
\n" ); document.write( "\n" ); document.write( "a) x^2+8x+7=0 I tried to solve it and I got this answer (x+1) (x+7)=0.\r
\n" ); document.write( "\n" ); document.write( "b) 2y^2 + 12y +10=0 I got: 2(y^2+6y+5)=0\r
\n" ); document.write( "\n" ); document.write( "c) x^2=81 I'm not sure how o solve this one.\r
\n" ); document.write( "\n" ); document.write( " However the =0 confuses me do I have to use the quadratic formula to solve them?
\n" ); document.write( "Thank you.
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Algebra.Com's Answer #377994 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I would not use the quadratic formula unless I really had to, and the instructions say to use factoring.
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\n" ); document.write( "a) \"x%5E2%2B8x%2B7=0\" You factored the quadratic polynomial to get \"%28x%2B1%29+%28x%2B7%29=0\".
\n" ); document.write( "For the product to be zero, one factor must be zero.
\n" ); document.write( "\"x%2B1=0\" gives you one solution: \"highlight%28x=-1%29\"
\n" ); document.write( "\"x%2B7=0\" gives you the other solution: \"highlight%28x=-7%29\"
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\n" ); document.write( "b) \"2y%5E2+%2B+12y+%2B10=0\" You factored the quadratic polynomial to get \"2%28y%5E2%2B6y%2B5%29=0\"
\n" ); document.write( "Factoring a little further, you get \"2%28y%2B1%29%28y%2B5%29=0\"
\n" ); document.write( "One of those factors must be zero.
\n" ); document.write( "\"y%2B1=0\" gives you one solution: \"highlight%28y=-1%29\"
\n" ); document.write( "\"y%2B5=0\" gives you the other solution: \"highlight%28y=-5%29\"
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\n" ); document.write( "c) \"x%5E2=81\" is easy, except for the question of using factoring.
\n" ); document.write( "\"x%5E2=81\" means that x is a number that squared equals 81.
\n" ); document.write( "You know one such number: \"9%5E2=81\" and \"highlight%28x=9%29\" is one solution.
\n" ); document.write( "There is also \"highlight%28x=-9%29\" because \"%28-9%29%5E2=81\" too.
\n" ); document.write( "Maybe you were expected to transform it by subtracting 81 from both sides to get
\n" ); document.write( "\"x%5E2-81=0\" and then factor to get \"%28x-9%29%28x%2B9%29=0\".
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