document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55718>Question 55718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given f(x) = 3x and g(x) = 3/x+1, find f/g(x) and state its domain.<BR>\n" );
document.write( "Please help! I don't even know where to start! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37798 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given f(x) = 3x and g(x) = 3/x+1, find f/g(x) and state its domain.<BR>\n" );
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document.write( "f(x)/g(x = (3x)/(3/(x+1))<BR>\n" );
document.write( "Invert the denominator and multiply to get:<BR>\n" );
document.write( "= (3x)(x+1)/3<BR>\n" );
document.write( "Cancel the common factor \"3\" to get:<BR>\n" );
document.write( "= x(x+1)<BR>\n" );
document.write( "The domain is all real numbers except x=-1<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );