document.write( "Question 596772: An aircraft flew 7 hours with the wind. The return trip took 8 hours against the wind. If the speed of the plane in still air is 336 miles per hour more than the speed of the wind, fond the wind speed and the speed of the plane in still air. \n" ); document.write( "

Algebra.Com's Answer #377878 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let

represent the speed of the plane in still air. Let

represent the wind speed.\r
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\n" ); document.write( "\n" ); document.write( "We are given that

mph, but

is also the ground speed against the wind, at which speed the aircraft required 8 hours to fly the distance. Hence the distance flown is

miles.\r
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\n" ); document.write( "\n" ); document.write( "From that we calculate the time for the downwind trip:

mph. But the ground speed downwind is given by

, hence:\r
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\r
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\n" ); document.write( "\n" ); document.write( "Solve the system for

and

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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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