document.write( "Question 596617: write the equation for the following asymptotes for the following hyperbola x^2-4y^2=16 \n" ); document.write( "
Algebra.Com's Answer #377814 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
write the equation for the following asymptotes for the following hyperbola x^2-4y^2=16
\n" ); document.write( "divide by 16
\n" ); document.write( "x^2/16-y^2/4=1
\n" ); document.write( "This is an equation for a hyperbola with horizontal transverse axis of the standard form: (x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center.
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "center:(0,0)
\n" ); document.write( "a^2=16
\n" ); document.write( "a=√16=4
\n" ); document.write( "..
\n" ); document.write( "b^2=4
\n" ); document.write( "b=2
\n" ); document.write( "..
\n" ); document.write( "slopes of asymptotes, m: ±b/a=±2/4=±1/2
\n" ); document.write( "equations of asymptotes:
\n" ); document.write( "y=mx+b and y=-mx+b, m=slope, b=y-intercept
\n" ); document.write( "y=x/2+b and y=-x/2+b
\n" ); document.write( "since asymptotes go thru origin, (0,0), y-intercept,b=0
\n" ); document.write( "equations therefore are:
\n" ); document.write( "y=x/2 and y=-x/2
\n" ); document.write( "
\n" );