document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=596545>Question 596545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a regular pool is 6 meters less than twice its width. If the pool's perimeter is 126 meters, what are its dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377779 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = width of the pool<BR>\n" );
document.write( "2x-6 = length of the pool\r<BR>\n" );
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document.write( "2W + 2L = Perimeter<BR>\n" );
document.write( "2(x) + 2(2x-6) = 126\r<BR>\n" );
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document.write( "2x + 4x - 12 = 126<BR>\n" );
document.write( "6x - 12 = 126<BR>\n" );
document.write( "6x=138<BR>\n" );
document.write( "x=138/6<BR>\n" );
document.write( "x=23 meters WIDTH<BR>\n" );
document.write( "2x-6=46-6=40 meters LENGTH\r<BR>\n" );
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document.write( "Chcck: 2*23 + 2*40=46 + 80 = 126  It checks!!!\r<BR>\n" );
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