document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55675>Question 55675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i KNOW THAT THIS IS PROBABLY A SIMPLY ONE BUT iM HAVING A TIME TRYING TO FIGURE HOW TO GET THE CORRECT ANSWER.  DMVT math student.\r<BR>\n" );
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document.write( "SOLVE FOR B: AX+BY=C.  how do you get an answer from this?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37775 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AX+BY=C  [Isolate the B]<BR>\n" );
document.write( "AX-AX+BY=-AX+C<BR>\n" );
document.write( "BY=-AX+C<BR>\n" );
document.write( "(1/Y)(BY)=(1/Y)(-AX+C)<BR>\n" );
document.write( "B=(-AX+C)/Y<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check by plugging [B=-AX+C)/Y] back into the original equation. </SPAN>\n" );
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